""" Koch Snowflake II 03.02.2022 (c) Juergen Meier (www.3d-meier.de) """ import c4d import random import math # Variablen und Konstanten Titel = 'Koch Snowflake II' # Name N = 1000000 # Anzahl Punkte Nv = 100 # Anzahl Punkte verwerfen dx = 1.50 # Breite Polygon dy = 1.50 # Hoehe Polygon Faktor = 1000 # Skalierungsfaktor s = math.sqrt(3.0) # Konstante xa = 0.5 a = 1/6.0 b = s/6.0 c = 1/3.0 d = s/3.0 e = 2/3.0 f = 1/2.0 def CreatePolygonObject(): obj = c4d.BaseObject(c4d.Opolygon) obj.ResizeObject(4*N, N) obj.SetName(Titel) # Startwert der Berechnung x = 0.5 xa = x y = 0.5 # Zaehler fuer Punkte setzten zz = 0 # Zaehler fuer Polygone setzten zzz = 0 for i in xrange(0,Nv): zufall = random.randint(0,6) if zufall == 0: x = -a*xa + b*y + a y = -b*xa - a*y + b if zufall == 1: x = a*xa - b*y + a y = b*xa + a*y + b if zufall == 2: x = c*xa + c y = c*y + d if zufall == 3: x = a*xa + b*y + e y = -b*xa + a*y + d if zufall == 4: x = f*xa - b*y + c y = b*xa + f*y if zufall == 5: x = -c*xa + e y = -c*y if zufall == 6: x = c*xa + e y = c*y xa = x for i in xrange(0,N): zufall = random.randint(0,6) if zufall == 0: x = -a*xa + b*y + a y = -b*xa - a*y + b if zufall == 1: x = a*xa - b*y + a y = b*xa + a*y + b if zufall == 2: x = c*xa + c y = c*y + d if zufall == 3: x = a*xa + b*y + e y = -b*xa + a*y + d if zufall == 4: x = f*xa - b*y + c y = b*xa + f*y if zufall == 5: x = -c*xa + e y = -c*y if zufall == 6: x = c*xa + e y = c*y xa = x obj.SetPoint(zz, c4d.Vector((Faktor*x-dx/2.0),(Faktor*y+dy/2.0),0)) zz=zz+1 obj.SetPoint(zz, c4d.Vector((Faktor*x-dx/2.0),(Faktor*y-dy/2.0),0)) zz=zz+1 obj.SetPoint(zz, c4d.Vector((Faktor*x+dx/2.0),(Faktor*y+dy/2.0),0)) zz=zz+1 obj.SetPoint(zz, c4d.Vector((Faktor*x+dx/2.0),(Faktor*y-dy/2.0),0)) zz=zz+1 obj.SetPolygon(zzz, c4d.CPolygon(zz-1,zz-2,zz-4,zz-3)) zzz=zzz+1 # obj.Message(c4d.MSG_UPDATE) return obj def main(): plyobj = CreatePolygonObject() # doc.InsertObject(plyobj, None, None, True) c4d.EventAdd() if __name__=='__main__': main()